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標題:

求向量電流V的相加

發問:

V(ao)=127 [94度],V(bo)=127 [-26度],(co)=127 [-146度] ,求V(ab),V(bc),V(ca)

最佳解答:

電流用I代表，電壓用V代表請查明 V(ab)= V(ao)- V(bo)= 127∠94 -127∠-26 =127(cos94+jsin94)-127[cos(-26)+jsin(-26)] =127[(-0.07+0.998j)-(0.899-0.438j)] =127(-0.969+1.436j) =220∠146 V(bc)= V(bo)- V(co)= 127∠-26 - 127∠-146 =127[cos(-26)+jsin(-26)] - 127[cos(-146)+jsin(-146)] =127[(0.899-0.438j) - (-0.829-0.559j)] =127(1.728+0.121j) =220∠4 V(ca)= V(co)- V(ao)= 127∠-146 - 127∠94 =127[cos(-146)+jsin(-146)]-127(cos94+jsin94) =127[(-0.829-0.559j)- (-0.07+0.998j)] =127(-0.759+1.557j) =220∠-64