標題:
f.1 math 一條
發問:
1/2(y+4)=y+1/8(4-y) 點計 列晒所有步驟
最佳解答:
1/2(y+4)=y+1/8(4-y) y/2+2=y+1/2-y/8 4y+16=8y+4-y 4y+16=7y+4 12=3y y=4
其他解答:
1/2(y+4)=y+1/8(4-y) y/2+2 =y+y/2-y/8 2-y/2=y-y/8-4/8y 1.5=3/8y 3/2*8/3=y 4=y y=4|||||y/2+2=y+1/2-y/8 y/2-y+y/8=1/2-2 -y/2+y/8=-3/2 -3y/8=-3/2 3y/4=3 3y=12 y=4|||||1/2(y+4)=y+1/8(4-y) 0.5(y+4)=0.125(4-y) 0.5y+2=0.5-0.125y 0.5y+0.125y=0.5-2 0.625y=-1.5 y=-2.4 y=-12/5
f.1 math 一條
發問:
1/2(y+4)=y+1/8(4-y) 點計 列晒所有步驟
最佳解答:
1/2(y+4)=y+1/8(4-y) y/2+2=y+1/2-y/8 4y+16=8y+4-y 4y+16=7y+4 12=3y y=4
其他解答:
1/2(y+4)=y+1/8(4-y) y/2+2 =y+y/2-y/8 2-y/2=y-y/8-4/8y 1.5=3/8y 3/2*8/3=y 4=y y=4|||||y/2+2=y+1/2-y/8 y/2-y+y/8=1/2-2 -y/2+y/8=-3/2 -3y/8=-3/2 3y/4=3 3y=12 y=4|||||1/2(y+4)=y+1/8(4-y) 0.5(y+4)=0.125(4-y) 0.5y+2=0.5-0.125y 0.5y+0.125y=0.5-2 0.625y=-1.5 y=-2.4 y=-12/5
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